Calculate The Depreciation with C

For my improvement, I follow the book that guide me into a topic of depreciation. The definition of depreciation itself: method of calculating the cost of tangible assets over it useful life.

For example, if a business purchases a delivery truch with a cost of Rp. 150.000.000 and it is expected to be used for 5 years. The business might have depreciation expense of expected years with the calculation :

first we sum of 5 years  :

 sum = 1+2+3+4+5=15 -->  15 can be formulated as 

 sum = n(n+1)/2

 n is for calculated years

The depreciation of every years can be like this:

• depreciation of 1 years: 5/15*Rp. 150.000.000 =  Rp. 50.000.000
• depreciation of 1 years: 4/15*Rp. 150.000.000 =  Rp. 40.000.000
• depreciation of 1 years: 3/15*Rp. 150.000.000 =  Rp. 30.000.000
• depreciation of 1 years: 2/15*Rp. 150.000.000 =  Rp. 20.000.000
• depreciation of 1 years: 1/15*Rp. 150.000.000 =  Rp. 10.000.000

In this learn, We will make a code how to  make a list of depreciation as above 

Here is the code I adopted from C handbook:

     ------------------------------------------------------------

#include<stdio.h>

main ()

{

long int cost;

int i, sum, year;

double deprec;

printf("Cost: ");

scanf("%d", &cost);

printf("Year: ");

scanf("%d", &year);

sum = year * (year+1)/2;

for (i=1;i<=year;i++)

{

deprec = (year + 1.0 - i)/sum*cost;

printf("%2d %.0lf\n", i, deprec);

}

return 0;

}

-------------------------------------------------

The outcome:

This program will show a fibonanci series like  1 1 2 3 5 8 13 .......

	#include<stdio.h>
	int main ()
	{
	int fn, fn1, fn2;
	fn1=1;
	fn2=1;
	printf("%4d", fn1);
	printf("%4d", fn2);
	fn=fn1+fn2;
	while(fn<=200)
	{
	printf("%4d", fn);
	fn2 = fn1;
	fn1 = fn;
	fn = fn1+fn2;
	}
	printf("\n");
	return 0;
	}

view raw fibonaci.c hosted with ❤ by GitHub

Calculator with C Language

Here I am with one program today :). And here is the code how to make simple calculator. Actually I copied the code from here, and tried to understand it. So simple and make sense. 

	#include<stdio.h>
	int main()
	{
	/*This is a calculator programme. Calculator is able to perform the operation of two numbers*/
	int num;float a,b,c;
	printf("Hello World this is a calculator ");
	printf("\nchoose a number from the menu to operate the desired function");
	printf("\npress 1 for addition\npress 2 for subtraction\npress 3 for multiplication\npress 4 for division \n");
	scanf("%d",&num);
	/*The operation is performed using the switch case method*/
	switch(num)
	{
	case 1:
	printf("enter two numbers \n");
	scanf("%f%f",&a,&b);
	c= a+b;
	printf("the addition of two numbers is %f",c);
	break;
	case 2:
	printf("enter two numbers \n");
	scanf("%f%f",&a,&b);
	c=a-b;
	printf("the subtraction of two numbers is %f",c);
	break;
	case 3:
	printf("enter two numbers \n");
	scanf("%f%f",&a,&b);
	c=a*b;
	printf("the multiplication of two numbers is %f",c);
	break;
	case 4:
	printf("enter two numbers \n");
	scanf("%f%f",&a,&b);
	c=a/b;
	printf("the division of two numbers is %f ",c);
	}
	}

view raw calculator.c hosted with ❤ by GitHub

It's been a while not to fill up this blog. By the way, I'm trying to collect some stuff in order to improve my C learning language.

Living in digital world and improving one of programming language is just like a need #programming #c #language

Foto kiriman Hani (read:honey) (@hanifadinna) pada Jan 20, 2016 pada 6:21 PST

Here is the code:

	#include<stdio.h>
	main ()
	{
	float i, j, h;
	printf("Enter the height of triangle: ");
	scanf("%f", &h);
	for(i=1;i<=h;i++)
	{
	for(j=1;j<=i;j++)
	printf("*");
	printf("\n"); // new line
	}
	return 0;

view raw triangle.c hosted with ❤ by GitHub